Question
At what speed in r/min should the 35 -in-diameter pump of Fig. $11.7 b$ be run to produce a head of 400 ft at a discharge of 20,000 gal/min? What brake horsepower will be required? Hint: Fit $H(Q)$ to a formula.
Step 1
Diameter (D) = 35 in = 35/12 ft = 2.917 ft Discharge (Q) = 20,000 gal/min = 20,000 * (1/264.172) ft^3/s = 75.67 ft^3/s Show more…
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