Question
At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at $-20{ }^{\circ} \mathrm{C} ?$ (atomic mass of Ar $=39.9 \mathrm{u}$, of $\mathrm{He}=4.0 \mathrm{u})$
Step 1
Step 1: We know that the root mean square speed (Vrms) is given by the formula: \[V_{rms} = \sqrt{\frac{3RT}{M}}\] where R is the gas constant, T is the temperature and M is the molecular weight. Show more…
Show all steps
Your feedback will help us improve your experience
Ajay Singhal and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at $-10^{\circ} \mathrm{C} ?$ (Atomic mass of $\mathrm{Ar}=39.9 \mathrm{u}$ and $\mathrm{He}=4 \mathrm{u}$ ) (a) $2.5 \times 10^{3} \mathrm{~K}$ (b) $3.5 \times 10^{3} \mathrm{~K}$ (c) $4.5 \times 10^{3} \mathrm{~K}$ (d) $2.9 \times 10^{3} \mathrm{~K}$
KINETIC THEORY
Kinetic Theory
At what temperature is the root mean square speed of Argon (Ar) gas equal to that of oxygen gas (O2) at 23°C? a) 237 °C b) 97 °C c) 509 °C d) 370 °C e) 29 °C
a) What is the root-mean-square speed of a Helium atom in Helium gas at STP? b) What temperature would oxygen gas have if the root-mean-square speed of its atoms was the same as in part a?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD