At what temperature (^∘ C) will 0.810 mol of chlorine in a 15.7-L vessel exert a pressure of 756

At what temperature (^∘ C) will 0.810 mol of chlorine in a...

Key Concepts

Ideal Gas Law

This law, expressed as PV = nRT, relates the pressure, volume, temperature, and amount of gas. It is a central principle in understanding the behavior of ideal gases and is used to compute any one variable when the others are known.

Pressure Unit Conversion

When solving gas law problems, it is important to convert pressure measurements into the appropriate units, typically atmospheres or Pascals, since the gas constant R is defined in terms of these units. Converting torr to atmospheres ensures consistency in calculations.

Temperature Conversion

Gas law equations require temperature to be in Kelvin, the absolute temperature scale. Converting from Celsius to Kelvin by adding 273.15 is essential for correct application of the ideal gas law.

Transcript

00:01 Right there.

00:03 This problem appears to be another ideal gas law equation problem.

00:06 So we are going to need the ideal gas law equation, which is pv equals nrt.

00:14 As we read through this problem, we see that we are trying to solve for temperature in degrees celsius.

00:22 So that's going to be important when we get to the end.

00:24 We're going to have to convert to degrees celsius.

00:27 Looking at the information given to us, we are given number of moles as 0 .810.

00:36 Moles of chlorine, we are given a volume of 15 .7 liters, a pressure of 756 tor.

00:58 So these are all the things provided in the problem.

01:01 The one thing that is not provided is a value for the universal gas constant.

01:05 But it is a constant, so your chapter has given you a couple of options to choose between.

01:11 I need to use the one that is recorded in tor, because i want the tor from our pressure that we're given to cancel.

01:21 So i'm going to select the 62 .4 liters times tor over mole kelvin.

01:35 All right.

01:37 Looking at back at the equation then, pv equals nrt.

01:40 If we are solving for t, before i plug these values in, i'm going to go ahead and rearrange the equation algebraically to solve for t.

01:48 So what that means is i am dividing both sides of the equation by nr.

01:55 That's going to give me t being equal to pv over nr.

02:03 Now we have all of our variables, except for one.

02:06 We have an algebraic equation...

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