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At what velocity does a proton have a 6.00 -fm wavelength (about the size of a nucleus)? Assume the proton is nonrelativistic. $\left(1 \text { temtometer }=10^{-15} \mathrm{m} .\right)$

$6.62 \times 10^{7} \mathrm{m} / \mathrm{s}$

Physics 103

Chapter 29

Introduction to Quantum Physics

Quantum Physics

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and this problem. We're asked to calculate the velocity of a proton with a six times 10 to the negative 15 meter wave wings, and we want to seem that the proton is non relativistic. So our weight length is equal to planks constant divided by linear momentum. So plants constant, divided by mass times velocity is are waving and our goal is to sulfur velocities. We can go ahead and multiplied by velocity and then divide by wavelength. So are velocity is planks divided by mass times the wavelength and we can go ahead and plug in our numbers. So we have 6.63 times 10 to the negative 34 Jules time seconds and our mass of a proton is 1.67 times 10 to the negative. 27 and our wavelength, Like we said, it was six times 10 to the negative 15. If I go ahead and plug in all of those values, I did get a 6.62 times 10 to the seventh meters per second velocity

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