00:01
All right, here we're told that the jerk is defined as the time rate of change of the acceleration is constant.
00:10
So we're told that this quantity is a constant.
00:18
And we want to compute the acceleration as a function on time, the velocity, and the position.
00:24
From this initial equation, which is a differential equation, we know that the acceleration then is going to be equal to the jerk times the time plus the initial acceleration.
00:37
So this is the acceleration as a function of time.
00:46
Then this is answering.
00:48
The velocity is equal to the differential, the derivative of the acceleration.
00:58
No, sorry, my apologies.
01:07
The acceleration, remember that it is the derivative of the velocity as a function of time.
01:16
So if we integrate using calculus, this equation on the right side, we get the velocity is equal to the initial velocity plus one half the jerk times square times square plus the initial acceleration times the time and if since we know that the velocity is the derivative of the position as a function of time which is what i wrote up above and we're going to grade this as a function of time we integrate this with respect to time we get at the position is the initial position plus the initial velocity times the time plus the jerk over 6 to cube plus the initial acceleration t squared over 2 and now we want to compute this the the changing acceleration times the changing velocity times the jerk.
02:47
We want to prove that...