00:01
Now we're asked to repeat the previous problem with a 7 .2 kilogram barbell and determine the force exerted at the del the force that the deltor exerts on the humorous and the force that the lifter shoulder joint exerts on the humorous all right, so we can basically repeat the problem before before, but now we have 7 .2 kilograms here everything else is the same, so we have our attention and we just have a different number for the weight of the barbells and plugging everything in, we get that that is 1 ,649 newtons.
00:39
Now we're also asked to figure out what these forces are in this problem.
00:44
So we know that if we sum the forces in the y direction, we have fy plus the y component of the tension in the deltoid, minus the weight of her arm, minus the weight of the barbell.
01:01
And in the x direction, we have the force at the joint in the x direction, and that has to balance the x component of t, which is t cosine theta.
01:15
And so we can, we have all these numbers, and so we can start plugging in...