00:02
So problem 37 is asking us to balance these chemical equations.
00:07
So this first chemical equation, we can look at the number of irons on this side and we see one.
00:13
On this side, we see two.
00:14
So that's even.
00:16
On this side we see that we have three chlorides.
00:19
So in order to balance on this side we need to add a three over here.
00:25
And now we can see that we have three potassium.
00:29
So to balance we need to go over here and add a three in front of this, k -o -h.
00:35
And now i see the that we have 3 .0h and 3 .0h on this side.
00:39
So this equation is balanced.
00:43
The next equation, we can start off by looking at lead.
00:46
There's one on this side and one on this side, so that's even.
00:50
We can see that the c2h3o2, there are two of them on this side.
00:56
So that means to balance, we need to add a 2 in front of that.
01:02
And then now we have 2 potassium.
01:05
And so to balance, we need to add a 2 in front of the k -i.
01:10
And now we have 2 iodine and 2 iodine to the side.
01:18
So that one's balanced.
01:20
The next equation, we can start off by saying, seeing that this is 4 phosphorus to balance, we need to add a 4 over here.
01:32
We can see that now we have 12 hydrogens.
01:36
So to make 12 hydrogens on this side, we need to add a 6.
01:43
And so we can see we have 16 oxygens on this side...