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Problem 40 asks us to balance these equations.
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For the first one, we have two sodium on the left, so we need two on the right.
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Now have two chlorine on the right.
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You have two chlorine on the left, so that's balanced.
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The next one, we need add three over here, so we have three irons on each side.
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We have four oxygens on the right, so we want to add a four here to get four oxygens in the left.
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And now that we have eight hydrogens on the left, i want to add a four over here.
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So we get eight hydrogens on the right.
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So now that's balanced.
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For this one, we have two chlorines on the right.
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So we want to add a two here.
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So we get two chlorines in the left.
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And now we have four hydrogens on the left.
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So we want to add a two here.
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So we get four hydrogens on the right.
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That also balances our oxygens with two on each side.
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For the next one, we have two bromines on the left.
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So we want to add a two over here, so we have two on the right.
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And now we have four hydrogens on the right.
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So we want to add two over here, so we get four hydrogens on the left.
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And now our oxygens are even with four on each side.
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So that equation is now balanced...