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Balance the following equations for combustion reactions. Circle the fuel for each reaction.a. $\mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$b. $\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$c. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$d. $\mathrm{C}_{21} \mathrm{H}_{24} \mathrm{N}_{2} \mathrm{O}_{4}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{NO}_{2}(g)$e. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH}(l)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{SO}_{2}(g)$

a) 2 $\mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})$b) $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{s})$c) $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(1)$d) $\mathrm{C}_{21} \mathrm{H}_{22} \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{s})$e) 2 $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH}(1)$

Chemistry 102

Chemistry 101

Chapter 19

Measuring Energy

Section 1

Combustion

Thermodynamics

Thermochemistry

Rice University

University of Kentucky

Brown University

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in problem for balanced each equation and circled e fuel for each reaction. So first equation is C two h six let's or two guests that will form carbon dioxide less h tour. So that means when 18 reacts with the oxygen, then it will produce carbon dioxide and water so we can balance this situation. So So this is the balance situation. Now we can multiply this situation by two, so multiply Bye. So So we get if we multiply distribution by two. Then we get this. This is C two at six plus or to gas that will form CO two. That's edge, toe liquid. So now, on multiple E occasion, this buy too. So we get to situate six and this is seven or two and this is 402 and this is six. So both the equation are balanced equation and the fuel fuel for this reaction is they see two at six. Or we can say that this All right, so in this SEC indication, So in this second equation, that is C six h 12 or six. So when this reactant reacts with the oxygen, then it will produce carbon dioxide and water now on balancing this situation, we get the sixth CEO toe and this six h two and then here we, you six, auto. So now this is the balance equation, and fuel for this reaction is the C six h 12 or six. So now, in this set, in the third part off the equation that is the C two h five or H. So this is the alcohol. So which is known as if I'll alcohol. So when this reacts with the oxygen guests, then it will produce carbon dioxide and water. And what so on balancing this aggression, we get so here we used to carbon dioxide. And this is the three H two and this is 33 or two. So now this is the balanced equation and fuel for fuel for this reaction is this C two h five h that we can say tile alcohol. So in the part d off the equation that is C 21 edge 24 and two or four. So this went reacts with the oxygen guest. Then it will produce carbon dioxide, water, carbon dioxide, less water along with and no two guests. Okay, so on balancing this occasion we get, we get here 21 co two and ah, total hydrogen on the left hand side, He's 24. So we can multiply this by 12. And okay. And now we can count the so nitrogen on the left hand side, these two so we can multiply this battle. So when we count the oxygen atom in the right side off the equation so we get total 58 oxygen atom is there. So so total 58 oxygen. So that means we can multiply desiccation by 27. So 27 into two. That is 54 plus four. So 54 plus four. So that means 58 oxygen. So now this is the balance situation, and the fuel for this reaction is they see 21 age 24 and to offer. And this is the balance equation. Okay. And the last part off the equation, that is C two h five. Shh. Liquid. So when this compound reacts with the oxygen, guess then it will produce carbon dioxide water and sulfur dioxide. So carbon dioxide and water and sulfur dioxide. So, on balancing this equation, we get on balancing, we get these two carbon dioxide because two atoms on the left hand side and two atoms of carbon in the left hand side. Now we can see this, uh, oxygen hydrogen. So total six hydrogen in the left hand side so we can multiply this occasion in the right hand side by six Such six h tour apps three h two. So basically three h two because three in 2 to 6 hydrogen. So now on. So hydrogen is balance. Carbon is also balance, and sulfur atom is also balance. Now, coming to the oxygen part, the total total oxygen atom in the right side, off the equation is four plus 379 So that was nine oxygen. So we can use this nine by two. So this is the balance equation, or we can multiply this equation by two in orderto more simplified. But again, this is balanced equation multiply battle. So we get the Cito H five message plus or to guess that will produce carbon dioxide gas plus H +20 and sulfur dioxide. So now when we multiply this situation by two, we get this to C two h h five message. Let's nine or two. This is for CO two, and this is six h two. And this is too. As so, both the equation that is balanced in the party and the fuel for this reaction is they c two h five message. Or we can say that this in this part off the equation. So that means the fuel in both the side off direction is same. So these are the balance situation and fuel for each reaction that is in the circle that is in the green on box for these equations.

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