00:09
Let's balance the half reactions in problem 4 .81, occurring in basic solution.
00:16
The half reaction for a is o2 gas into oh minus aqueous.
00:25
Balance the oxygens by adding h2o on the right.
00:29
There are three hydrogens on the right, so i need 3h plus on the left.
00:35
To balance the charge.
00:38
I will need four electrons on the left.
00:41
Let's convert this to basic by adding in 3h plus, 3 .0 minus, 3h2o.
00:53
H2cels to give me 2 .h plus.
00:57
I'm left with o2 gas, 2h2 liquid, 4 electrons and 4 .0 .h minus aqueous.
01:12
So there's my balanced half reaction in basic conditions.
01:16
For b, i have h2o2 aqueous to o2 gas.
01:27
So oxygians are already balanced.
01:30
I will need 2h plus and two electrons.
01:37
To balance.
01:38
Now we'll switch to basic.
01:41
2h plus, 2 .0 minus 2h2.
01:48
H2, h22, and 2oh2, 2h2, and 2h2, 2h2, and two electrons.
02:05
For c, mno4 minus to mno42 minus aqueous...