00:01
Let us first calculate the area of the cross section.
00:03
So it will be area is equal to length multiplied by width.
00:07
So it is 1 .5b multiplied by b.
00:11
So it is equal to 1 .5b square.
00:17
The moment of inertia about y -axis will be equals to bh cube divided by 12.
00:24
So it is equal to 1 .5b multiplied by b cubed divided by 12.
00:31
So it is equal to 0 .125 0 .125 b to the power of 4.
00:45
And also now let us calculate the value of radius of gyrrace and about y -axis.
00:51
So it is equal to iy divided by area.
00:55
So it is equal to square root of 0 .125 b2 the power of 4 divided by 1 .5 b2 b squared so it will give us a value of 0 .2 double 8b.
01:13
Now let us calculate the allowable stress.
01:16
So sigma allowable, this will be equals to force divided by area.
01:21
Force divided by area.
01:23
Now the force is 0 .8 and the area is 1 .5b square.
01:30
So it will give us a value of 0 .5 .3 divided by b square...