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All right, guys, we're doing problem 104 in chapter 8 to chemistry and central science.
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So barium azide is 62 .0 % barium and 37 .9 % nitrogen.
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Azoid has a net charge of minus 1, determine the chemical formula of azide.
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Azoid.
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So we're going to do this.
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So 62 .04 times 2 .04 grams.
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We're assuming we're dealing with 100 grams substance.
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1 mole, or 137 .3 grams equals 0 .518 mol, baryum.
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And for azo, 37 .96 grams.
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We can look up the molecular weights of nitrogen.
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It's going to be 14 .01 grams per mole.
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That's going to equal 2 .710 moles of nitrogen.
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So then we divide this, so 2 .710 over 0 .4158.
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That's approximately going to be equal to 6.
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So we have our formula b, a, and 6.
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Now, barium has a plus 2 charge, and azide as minus 1.
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So we're going to have two azide molecules.
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So that means that every azide molecule is going to be n3.
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So that's going to be azide and 3 minus.
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So, why 3 resinous structures for the a -zide molecule? so a -zide can come from this, this, so this is going to be plus 1 and minus 2, 2.
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It can be like this...