00:01
Three resistors are arranged in series.
00:04
R sub 1 and r sub 3 are given, but r2 is not.
00:08
The connection is connected to a voltage source of 15 volts.
00:14
And as shown in the diagram, there is a current of half an ampere.
00:18
Question 51, what is the equivalent resistance of the circuit? four choices are given to us.
00:25
To help us answer the question, we need to apply the characteristics of the electrical quantities in resistors in series.
00:36
So we have it here in red ink, wherein you have the total resistance or the equivalent resistance is equivalent to the summation of the resistances.
00:47
You also have here the total current, which is equivalent to the individual currents.
00:52
And the total voltage is the sum of the individual voltages.
00:56
So i hope you agree with me that our main working equation, of course, is the first one, this one.
01:03
However, our problem is we do not know resistance to yet.
01:07
So we need to find resistance to first before using this equation for equivalent resistance.
01:16
Okay.
01:17
So since this is series, resistors in series, we know that this 0 .5 ampere is the same current that flows through resistor 2 and the same current that flows through resistor 1.
01:32
Therefore, we can determine the voltage across resistor 1 and determine the voltage across resistor 3 so that you'll be able to determine voltage across 2 and thereby get resistance 2.
01:48
Okay, so let's do that step by step.
01:50
First, let's determine voltage across resistor 1 first, applying oms slope.
01:57
So it's just i1 times r1.
02:00
We have half an ampere times 5 oms.
02:05
So the voltage across resistor 1 is 2 .5 volts.
02:12
In other words, out of the 15 volts, it's only 2 .5 that is across r1.
02:21
So the series circuit here is actually a voltage divider because the 15 volts here gets to be distributed across each resistance.
02:32
Okay.
02:33
Now let's find the voltage across resistor to applying the same logic.
02:40
So this is still the current.
02:42
I'm sorry, this should be voltage 3.
02:45
Okay.
02:46
So the current through voltage 3 is 0 .5 amp...