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BASEBALL For Exercises $36-38$ , use the following information. Albert and Paul are on the school baseball team. Albert has a batting average of $.4,$ and Paul has a batting average of 3 . That means that Albert gets a hit 40$\%$ of his at bats and Paul gets a hit 30$\%$ of his times at bat. What is the probability that-
neither Albert nor Paul is able to get a hit their first time at bat?
.42$(42 \%)$
Intro Stats / AP Statistics
Algebra
Chapter 12
Probability and Statistics
Section 5
Adding Probabilities
Sampling and Data
The Normal Distribution
Introduction to Combinatorics and Probability
Missouri State University
Oregon State University
Harvey Mudd College
University of Michigan - Ann Arbor
Lectures
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So this problem. We want to find the probability that neither Paul nor Albert gets a hit their first time at bat. So if Albert's percentage is point for or four out of 10 and Paul's is 0.3 or three out of 10 I want to find the probably that neither of them get a bat. So we actually take these and we subtract them from 100 that will give us six out of 10 and that will give us seven out of 10. So these are the percentages that Albert will miss. His first time is bad, and this is the percentage that Paul will miss the first time that we want to find the probability of something not happening. It's one minus the probability of it happening. So we want to take these and we want to multiply these together and we should end up with 42 over 100 simplifies down 2.42 and in order to turn into a fraction we want multiplied by 100 that will give us 42%. So that is the percentage that neither of the boys get their hit their first time. I'm bad
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