00:01
We have a problem in which we are to simplify an expression that involves the sign and the inverse sign.
00:09
This problem will require using a property that relates the inverse sign and the sign of an angle.
00:17
So this property says that the inverse sign of x is equal to x.
00:24
Again, the inverse sign of the sign of x is equal to x where x is between and including negative pi over 2 and pi over 2.
00:38
So we look at the problem and look at the angle that we're given.
00:42
The negative 10 pi over 9 is not between negative pi over 2 and pi over 2.
00:50
So we need to work with coterminal and reference angles to find an angle that we can use here that does fit this range of angles.
01:02
So the first thing i'm going to do is i'm going to get a coterminal angle.
01:10
So i'm going to take the negative 10 pi over 9 and add 2 pi to it.
01:17
And i'm adding 2 pi because i'm going to try to get that angle positive.
01:21
So that's a negative 10 pi over 9 plus 18 pi over 9, which is 8 pi over 9, which is still not in the range of angles that we need.
01:43
It's still a little bit too big.
01:44
So 8 pi over 9 is a second quadrant angle...