00:01
The load supported by a horizontal beam varies jointly as the width of the beam and the square of its depth.
00:12
So the width would be w, a better w, the width would be w.
00:18
I'm going to use t for thickness, and it's the square of that, and inversely as the length.
00:29
So it's divided by length, and we need a constant.
00:33
So how does the maximum safe load change under this condition? so let's say the width and the length are doubled.
00:49
So now w is equal to 2 times w and l or length is equal to 2 times the length.
00:57
Well let's see what that looks like in the equation.
01:00
So the load is equal to the constant times 2 w t squared over 2 l.
01:09
Well, those twos cancel out, effectively there are one.
01:15
So there is no change.
01:21
It's the same thing as the original expression.
01:27
Now let's look at what would happen if the width and depth are doubled.
01:33
So now the width is doubled, and so is the depth...