because-a-sled-slides-from-rest-down-an-icy-slope-measurements-taken-from-a-video-show-that-the-dist

Question

$\because$ A sled slides from rest down an icy slope. Measurements taken
from a video show that the distance from the starting point to the
sled at various times is as follows:

(a) Plot the position of the sled versus time. (b) From your plot,
determine the approximate average speed of the sled from
$t=0.25$ s to $t=1.3 \mathrm{s}$ . (c) Determine the approximate accelera-
tion of the sled, assuming it to be constant.

Nathan Silvano · Accepted Answer

Okay, so in this problem, we have a table of measurements and we have to plot the graph off these measurements. This is this is the movement of his lad. So let&#x27;s see, the first point is, in 0.5 seconds and zero point dirty seeks. Let&#x27;s see. You know 0.36. It&#x27;s great to be one. This is one so 0.36 beat something like here. You did it for you. 36. This is the first point. Okay, the second point is one with 1.3. Oh, also is going to be something like here. The next point is 1.5 and 3.2 0.2 is 1233.2, actually, around here, next point is in two seconds and 5.7 I&#x27;ve is 123455.7. Something like you. The next one. And final one is 2.5. Your point. First on, we grows way up into eight points. Eight. So if we connect all the dots and going to have behavior, it is something like a parable. So the first item we plot a graph in we know it sir Credible. The second item we need to tell the average velocity between the times. Judo 0.25 up into time. 1.3. Wrong 0.3 seconds. Okay, so if you look to the graph, 1.3 seconds is actually let&#x27;s be convicted. Smaller one 0 25 is actually pretty. It&#x27;s pretty close to zero points. 18. So we can say that the position of 0.25 0 point 18 and the positions of 1.3 just something like you could be close two close to 2.3 2.3 meters so we can calculate the average. It&#x27;s Pete just going to be 2.3 minors, you know, 0.18 divided by 1.3, minus 0.25. And this is going to be equal to closer to 2.2 meters per second. That&#x27;s the answer. The first, the second item on the final right. And we need to discover the acceleration well. To discover the acceleration, we just need to use one of the creations of motion. We know that the position as a function off time, it&#x27;s written us. Excuse us zero t with us a he squared, divided by two. So we know that this light starts from rest. Rich means his initial velocity is going to be zero. So we just need to be one of the segments that we have. Let&#x27;s pick bigger wrong 2.5 in 8.8. Going to have 8.8 of distance equals a divided by two 2.5 square. So then we have to the acceleration off this light going to be 8.8, divided by 2.5 square times. Two. This is equal to two point 2.8 16 meters burst seconds square, and that&#x27;s the final answer to this problem.

Ankit Gupta · Answer

it is given that as softy is defined as as soft A is equal to be 1.5 p when the value of 50 is greater than or equal to zero and less than record to 16 on the valley off as softy is equal to be 24 divided by T minus 15 when the value off T is greater than or equal toe 16. Now we need to find the value off as off zero. Never putting P is equal to zero we have as a zero is equal to be 1.5 deployed visit. Oh, that is equal to be zero feet per second. Now we need to find the yellow as often number putting physical do 10 we have the badly off has often musical Toby 1.5 deployed with 10 that is equal to be 15 feet But second now we need to find their lives as soft 16 never put 20 is equal to be 16 We have the badly off s off 16 is equal Toby, 1.5 multiplied with 16 which is equal to be 24 feet. But second now we&#x27;re putting the value we need to find the value of us off 20. Never putting t is equal to 20. We have the value of us off Twente&#x27;s equal. Toby 24 divided by 20 minus 15 is equal. Toby 24 upon five, which is equal to before 50.8 feet. But second Now we need to find the value off as off 25. Now putting T is equal to 25. We have the value as of 25 is equal. Toby 24 divided by 25 minus 15 which is equal to be 24 upon 10 which is equal to be 2.4 feet. But second now, by using these five values, we have the points 00 the 00.10 coma, 15. The 150.16 comma 24. The 240.20 comma 4.8. The 0.25 Commodore Been foot. Now, by using these five points, we need to floor to the graph off the given function Esti. Now, by floating these points on the graph and by joining them, we have the graph of the function as safety will look like. As so, this is the required graph off the given function as softie. So this is our answer

Dading Chen · Answer

Okay, so we know the impulse is equal to the change of momentum which will give us f axes. Um, Tele be FX is the force and he&#x27;s a time and was a Mastella. B is the change of speed which will give us m 10 speed humans. We a baby is a final speed and we use the initial see things eyes move wrong point A to point B. So therefore, Web times ago M v b minus v a over FX. So the force in this case is actually a friction which is you connect them you and the reason was inactive because is opposed emotion. Okay, so it&#x27;s opposing the motion. So is in along the ups direction off the motion. So therefore we know that normal forcing in this case is gravity because it&#x27;s horizontal service. So lyrical have Negm UMG musical friction. The level of the TZ with m task will be mind to be a over Legum umg, as you can tell. Mm Kim cancel. So therefore we have teas. You will we be mass we overnight community. So then we can determine the time which is equal to five meter per second, minus a meter per second over negative. 0.25 times 9.8 meter per seconds were. And this will give us the time is about one point. So two seconds. So you take about 1.23 seconds. Well, the slack to trial front a pulling a point Angel point be okay. And this is the answer for this quest.

Mitchell Riley · Answer

were given that our distance d is 2000 feet and our angle data is 30 degrees and we want to find how long it takes MM. For this sled, too. Though this amount of time at this angle and T is given by this relationship. T over D. T is the square root of de times D over 16 times. Sign of Veda. So I&#x27;m just gonna plug in D and data so we&#x27;ll have 2000 over 16 times Sign 30 degrees and the sign of 30 degrees is 1/2. So love 2000 better by 16 times 1/2 and that&#x27;s gonna be square It 2000 divided by 16 times half is just eight and 2008. Out of 2008 8 to 50 we&#x27;ll have squared of 2 50 this is equal to 15.81 So it takes this long for the sled to get down the hill

Maninder Singh · Answer

it is given. De Ik was scared off the over 16 sign where these the length of this law and he does that in claimed. And in this case, it is given the equals two Tozser and Tita equal started degree. So we would write like this The EQ Waas scarily off 2000 or 16 Sign 30 16 signed 30 And we know that scientist is 1/2 for rebels. All this does scared off 2000 or 16 and signed 30 is 1/2. No, If we cancer toe turn 16 we will get it. So it becomes scared off who? 1000 were it again? When we have to solve them, we will can sell 2000 And it it means we will divide the Hotel Jinbei here and we will get 250. So therefore e equals scared off who? 100 50. No, we have to find a square root of 250 by making use of calculator. You can find this thing also or you can also make factors like this. So 1 20 for you time stool and we can again fact price 1 25 years by eyes for you times for you and times Do No If we have to make pairs so we will make pairs off I Then we will get the equals. E was I scared off. So which is the required and sir for the given problem? Five on the route step.

Julie Farhm · Answer

and this problem were asked to find the acceleration of a snowmobile. According to a velocity time graph that&#x27;s given, there&#x27;s three sections of the graph section A. The velocity starts at zero and it goes to a speed of 40 or velocity of 40 and the time interval or which that occurs. The initial time is zero, and the time at the later point is about 21 seconds. So to find the slope we do, the rise over the run and slope indicates the acceleration when you&#x27;re looking at a velocity time graph, so the rise would be the change in velocity. So 40 meters per second, minus zero and the time interval is a change from 0 to 21. So our acceleration for that 1st 2nd 1st section is going to be 1.9 meters per second per second, or 1.9 meters per second. Squared section B is horizontal, it&#x27;s flat, so the velocity in the beginning of the section is 40 meters per second and the velocity at the end of the section is 40 meters per second. The time interval happens to be about 28 seconds, but it doesn&#x27;t matter because the change in velocity is zero. So the acceleration will be the change in velocity or the change in time. And that will be zero. The third section we&#x27;re going from velocity of about still 40. The initial is 40 and it goes up to a velocity of 80 the time interval over which that happens. It&#x27;s just a little over 10 seconds that give it about 12. Where because the initial time for this section is 48 seconds or so and the final time for this section is 60 seconds. So our acceleration then will be the change in velocity 80 minus 40 meters per second, divided by the time interval 60 minus 48. So 40 on the numerator divided by 12 of the denominator is 3.3 leaders per second Squared these air both positives because the acceleration is up can&#x27;t seem to right there, he says. Positive also and we are finished

Problem

$\cdot$ A child slides down a hill on a toboggan …

Problem 47 Hard Difficulty

Answer

(a) The graph seems to be close to a parabolic curve.
(b) 2 $\mathrm{m} / \mathrm{s}$
(c) 2.816 $\mathrm{m} / \mathrm{s}^{2}$

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(a) The graph seems to be close to a parabolic curve.(b) 2 $\mathrm{m} / \mathrm{s}$(c) 2.816 $\mathrm{m} / \mathrm{s}^{2}$

Physics

Elyse G.

Farnaz M.

Jared E.

Meghan M.

Math Review - Intro

Algebra - Example 1

James S. WalkerPhysics

Elyse G.

Farnaz M.

Jared E.

Meghan M.

(a) The graph seems to be close to a parabolic curve.
(b) 2 $\mathrm{m} / \mathrm{s}$
(c) 2.816 $\mathrm{m} / \mathrm{s}^{2}$

James S. Walker

Physics