00:01
Okay, so in this problem, we have a beam of unpolarized light, and we have three filters.
00:10
The first filter has an angle, let's call, teta 1 of 0 degrees with the vertical.
00:22
The second filter, let's call this filter blue.
00:25
He has an angle with the vertical that we're going to call teta 2, because we do not know yet what it is.
00:40
And the turn filter, which is going to be the green filter, also has an angle with the vertical that is, that we're going to call teta 3.
00:56
So what we have to calculate is a angle with the vertical that is, that we're going to call theta 3.
01:00
In here.
01:03
We have to calculate the intensity of the transmitted bin after passing for the three polarizers knowing that the initial intensity of the of the beam let's put in here this color the initial intensity is just 1 .6 watts per meter square.
01:30
So remember that to calculate the intensity of the beam after passing through the first polarizer, we just have the original intensity decreased by half because the beam was unpolarized light.
01:51
And when we passes unpolarized light through a polarizer, we have the original intensity decreases by half.
02:01
So this is intensity of the transmitted beam.
02:05
The transmitted beam.
02:08
The second polarizer we have y2 in here.
02:13
This is just y1, cosine square of theta 2...