$\because$ What area is needed for a solar collector to absorb 45.0 $\mathrm{kW}$ of
power from the Sun's radiation if the collector is 75.0$\%$ efficient?
(At the surface of Earth, sunlight has an average intensity of
$1.00 \times 10^{3} \mathrm{W} / \mathrm{m}^{2} . )$