Question
$$\begin{aligned} f(x) &=\frac{1}{x} \\ x_{0} &=\frac{1}{2} \\ L &=2 \\ \epsilon &=0.01 \end{aligned}$$
Step 1
01$. We want to find a delta $\delta$ such that if $0 < |x - x_{0}| < \delta$, then $|f(x) - L| < \epsilon$. Show more…
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