00:01
So in part a, we're doing an anova test with the values.
00:05
And i have my data stored in list one, list two, and list three.
00:10
And we find that our f statistic is equivalent to 51 .8 and 18.
00:19
And the p value for this is equal to 1 .2 times 10 to the negative 6th power.
00:27
And we're using an alpha level of 0 .05.
00:30
And we were assuming that the mean from a is equal to the mean from b is equal to the mean for c, and alternately that not all above are equal.
00:48
And so we definitely have evidence at a 5 % significance level to reject the null.
00:58
Now, part b, we want to use the technique that they show us, that fisher technique, to show if there are differences between a and b.
01:07
So we would start out with whether the mean of a is equal to the mean of b, and alternately that the mean of a is not equal to the mean of b.
01:20
And our test statistic is to take, which will be a t value, and our number of pieces of data, n total, was 15, and we have a k value of 3.
01:33
So our degrees of freedom will be 12.
01:37
And we'll have, and this is a two -tail test because we're doing a not equal to.
01:41
And we take the difference between the two means, and that is 30 minus 45.
01:47
And then we take the square root of, and we need to have what the mean square error is.
01:52
And from my analysis, i have the mean square of the air is 5 .5, and that's times one over the sample size of the first group and one over the sample size of the second.
02:03
Group and so we'll end up having let's see that's going to be negative 5 divided by the square root of and we'll have that 5 .5 times in this 5 .5 and it will be times put in a decimal point rather than times and then this will be two -fifths times two divided by five and that gives us a test statistic of negative 3 .37 and that p value is going to be this like of being in that lower tail and then times two.
02:40
So let me quick get that for use.
02:41
The second distribution, my tcdf, and i can plug in that negative 3 .37.
02:50
And then my degrees of freedom is my 12.
02:53
And we'll paste that down.
02:55
And then i'm going to multiply that by 2.
02:57
And this is going to be a small p value.
02:58
It's only 0 .0056.
03:01
And this is less than 0 .055.
03:03
So therefore, we would reject the null.
03:07
So we do have evidence that these two are different.
03:11
Now we can carry on and do the same thing for doing the comparison between, and i'm just going to put the between b and c...