Question
$\begin{aligned}x+2 y+z &=0 \\3 x+2 y-z &=4 \\-x+2 y+3 z &=-4\end{aligned}$
Step 1
Step 1: First, we subtract equation 1 from equation 2: \begin{align*} (3x+2y-z) - (x+2y+z) &= 4 - 0 \\ 2x &= 4 \\ x &= 2 \end{align*} Show more…
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