### How are parts by mass and parts by volume used in…

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Johns Hopkins University
Problem 15

$$\begin{array}{|c|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} & {5} \\ \hline y & {\frac{11}{4}} & {\frac{25}{4}} & {\frac{39}{4}} & {\frac{53}{4}} & {\frac{67}{4}} \\ \hline\end{array}$$
Which of the following equations relates $y$ to $x$ for
the values in the table above?
$$\begin{array}{l}{\text { A) } y=\frac{1}{2} \cdot\left(\frac{5}{2}\right)^{x}} \\ {\text { B) } y=2 \cdot\left(\frac{3}{4}\right)^{x}} \\ {\text { C) } y=\frac{3}{4} x+2} \\ {\text { D) } y=\frac{7}{2} x-\frac{3}{4}}\end{array}$$

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SAT
SAT Practice Test # 6

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## Video Transcript

Okay, So for this one, we want to find how it we can relate. Accident? Why here? So that's going to look at the increases. So from exit just those two plus one plus one plus one plus one. So it's a constant reek on there for the Y, going from eleven to twenty five of four. We're adding fourteen over four from twenty five over four to thirty nine over four. We're also adding fourteen over four. If you want to know how I got that, I just did. Thirteen. Thirty nine over four, minus twenty five over for about fourteen over for now. Also did twenty five over four minus eleven over four. Got forty, number four to clear. We're we're just getting the same amount, fourteen over for each time. So then if we want to find that equation because we know that the accent, what increases our constant. We know that it has to be a linear equation, so that means it automatically can't b and B because those ones have both exponential. So they're out of Sandy. We just have to find which, when it can be, and so let's think about what it means for us to be linear. Well, that means that follows the wise equals MX plus B equation for M is the slope. Well, we know that the slope is just the change in y over the change in X, we found her change. My and we also find changing X so you can just train Take that changing Why was was there fourteen over four and divide that by one which was our changing ex which is just fourteen number four. But then from here we know that these are both even numbers so we can simplify that two seven over to by dividing both the top and bottom I too. So we know that he has to be a correct answer because that one has a slip of seven over too.