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Problem

$$ \begin{array}{l}{\text { The density of an obj…
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Averell H.
Carnegie Mellon University

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69

Problem 65 Medium Difficulty

$$
\begin{array}{c}{\text { The American Lung Association gives the following formula }} \\ {\text { for an average person's expected lung capacity } V \text { (in liters, }} \\ {\text { where } 1 \mathrm{L}=10^{3} \mathrm{cm}^{3} ) \text { : }} \\ {\quad V=4.1 \mathrm{H}-0.018 \mathrm{A}-2.69}\end{array}
$$

Answer

Unit of 2$\cdot 69$ $=L$

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Physics 101 Mechanics
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Chapter 1

Introduction, Measurement, Estimating

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Discussion

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Kj

Keith J.

September 13, 2020

Is the equation v2 = 2ax dimensionally correct? v is the speed [L/T] of an object, a is the object's acceleration [L/T2] and x is the distance traveled [L]

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Divide.
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Simplify.
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$$\begin{array}{l}{\text {…

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Solve and check each equat…

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13. $$v^{\prime \prime}+4 …

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Solve each equation, and c…

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Simplify.
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What fraction subtracted f…

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Solve each equation.
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Find $\mathbf{u}-\mathbf{v…

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Watch More Solved Questions in Chapter 1

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69

Video Transcript

so the units for each term must be in leaders because the units for volume is is leaders. So we can say that the units for the 4.1 em ah would be equal to Oh so essentially, units for 4.1 would be equal to leaders divided by meters and or its story leaves about of my mass. Uh, we can say that the units for the 0.18 times why ah, this again has to be in terms of leaders. So we can say units for off 0.18 would be, of course, equal to out over why. And lastly, the units for 2.69 must be in leader's cause. There's no there's nothing being multiplied by 26269 So 26992.69 must have a unit of leaders. That is the end of the solution. Thank you for watching

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Physics for Scientists and Engineers with Modern Physics

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Solve each equation, and check your solution. $$ 9(v+1)-3 v=2(3 v+1)-8 $$

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Subtract. $$\begin{array}{r} 17 v+3 \\ -\quad 2 v+9 \\ \hline \end{array}$$

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