Question
$$\begin{array}{l}\mathbf{r}^{\prime}(t)=-2 \sin t \mathbf{i}+6 \cos t \mathbf{j} \\\mathbf{r}^{\prime}(\pi / 6)=-\mathbf{i}+3 \sqrt{3} \mathbf{j}\end{array}$$
Step 1
Step 1: First, we write down the given function $\mathbf{r}^{\prime}(t)=-2 \sin t \mathbf{i}+6 \cos t \mathbf{j}$. Show more…
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