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$$\begin{array}{l}{\cdot \text { A coal-fired power plant that operates at an efficiency of }} \\ {38 \% \text { generates } 750 \mathrm{MW} \text { of electric power. How much heat }} \\ {\text { does the plant discharge to the environment in one day? }}\end{array}$$
$1.1 \times 10^{14} \mathrm{J} / \mathrm{day}$
Physics 101 Mechanics
Chapter 16
The Second Law of Thermodynamics
Temperature and Heat
Thermal Properties of Matter
The First Law of Thermodynamics
University of Michigan - Ann Arbor
University of Washington
Simon Fraser University
University of Sheffield
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in this problem. Patrol. We have a coal fired power plant that operates at an efficiency of 38% generates 750 megawatts of electric power. How much heat does the plant dis tribes to their environment in one day? So the power out is 750 megawatts, and the power out is the efficiency times the power. So the power in this 700 meg you 750 megawatts divided by 0.38 and that ISS 1974 make watts so the rate of power go, um, to the environment. ISS the power in minus the power out and that's 1224 megawatts of the amount of power in a day is 224 times 10 to the sixth Jules per second times one day times 24 hours a day Time. 60 minutes in an hour have 60 seconds in a minute, and we get 1.1 times 10 to the 14th Jules per day
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