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Estimate the number of gumballs in the machine of…

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Averell H.
Carnegie Mellon University

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69

Problem 47 Hard Difficulty

$$ \begin{array}{l}{\text { An average family of four uses roughly } 1200 \mathrm{L} \text { (about) }} \\ {300 \text { gallons) of water per day }\left(1 \mathrm{L}=1000 \mathrm{cm}^{3}\right) . \text { How much }} \\ {\text { depth would a lake lose per year if it uniformly covered an }} \\ {\text { arca of } 50 \mathrm{km}^{2} \text { and supplicd a local town with a population }} \\ {\text { of } 40,000 \text { people? Consider only population uses, and }} \\ {\text { neglect evaporation and so on. }}\end{array} $$

Answer

9 $\mathrm{cm} / \mathrm{year}$

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Video Transcript

so we want to do we want to find the death loss for the lake per year so we can say that the volume of water used by the people per year we can say that's around the lake. There are four times 10 to the fourth people that are drawing water from this lake and then at a rate of 1200 leaders per day for a single family. So we can say for people and then we're going to multiply it by 365 days in one year and then we can multiply that by 1000 cubic centimeters per one leader and then we want to playing that by one kilometer for every 10 to the fifth centimeters Quantity cube. And so we find that the use the usage would be 4.38 times 10 to the negative third cubic kilometers per year. And so at this point, we can say that the depth of the water is going to be equal to the volume of the water divided by the area, the surface air, the surface area of the lake, and this is gonna be equal to 4.38 times 10 to the negative third kilometers cubic kilometers per year. So that would be the volume that is being used divided by the surface area of the lake that is exposed thio essentially this week. If we wanted to model the lake as a cylinder Uh, the cross sectional area of the lake. Yeah, Kilometers squared. And so we can say that this is gonna be equal to 8.76 times 10 to the negative fifth, uh, kilometers per year and we should convert so we can say 10 to the fifth centimeters for every one kilometer. So the death would be essentially decreasing at a rate of 8.76 centimeters per year. That is our final answer. That is the end of the solution. Thank you for watching.

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Physics for Scientists and Engineers with Modern Physics

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