Using the product rule, where \( u = x \) and \( v = (x-6)^2 \), we have:
\( f'(x) = u'v + uv' \).
First, find \( u' \) and \( v' \):
\( u' = 1 \) and \( v = (x-6)^2 \).
Using the chain rule, \( v' = 2(x-6) \cdot 1 = 2(x-6) \).
Thus,
\( f'(x) = 1
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