Question
$$\begin{array}{l}{\text { Volume Consider the region bounded by the graph of }} \\ {y^{2}=\frac{(2-x)^{2}}{(1+x)^{2}}} \\ {\text { on the interval }[0,1] \text { . Find the volume of the solid generated }} \\ {\text { by revolving this region about the } x \text { -axis. }}\end{array}$$
Step 1
In this case, $y^{2} = \frac{(2-x)^{2}}{(1+x)^{2}}$ and the interval is $[0,1]$. So, the volume is $\pi \int_{0}^{1} \frac{(2-x)^{2}}{(1+x)^{2}} dx$. Show more…
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