00:01
Our task today is to find the limit as x approaches zero of f of x and f of x is given as the square root of 3 plus x minus the square root of 3 divided by x.
00:14
So if we set up a table, we can see that the closer we get to 0, the closer the value is going to be to 0 .887 or plus or minus 0.
00:31
Point, i mean minus, probably minus minus, minus 0 .0 .001.
00:40
Okay, and that's that if you're interested in what the value is, there you go.
00:47
But i would like to do it in a more analytical way.
00:52
So let's get started.
00:54
Now if you remember back in algebra two, there is this method of, manipulating functions.
01:03
It's called multiplying with the conjugate.
01:07
So if you have a minus b, if you multiply it by a plus b, you will get a squared minus b square.
01:16
You will recognize this as the difference of squares formula.
01:23
So we're going to use this formula here to help us with manipulating this function in order for us to make use of the information that we're given.
01:38
So look at the numerator.
01:41
We see that we have this term minus that term.
01:45
Well that kind of looks like a minus b, right? and our a is the first term and b is our second term...