Benzene has a heat of vaporization of 30.72 kJ / mol and a normal boiling point of 80.1^∘ C . At

step 1 My name is Ahmad Ali in this question. He wants to know the temperature and pressure. When we ch

Benzene has a heat of vaporization of 30.72 kJ / mol and a...

Benzene has a heat of vaporization of 30.72 $\mathrm{kJ} / \mathrm{mol}$ and a normal boiling point of $80.1^{\circ} \mathrm{C}$ . At what temperature does benzene boil when the external pressure is 445 torr?

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Key Concepts

Boiling Point and Vapor Pressure

The boiling point of a liquid is defined as the temperature at which its vapor pressure equals the external pressure. This concept is fundamental in understanding how phase changes occur, particularly during the transition from the liquid state to the gaseous state in different pressure environments.

Clausius-Clapeyron Equation

The Clausius-Clapeyron equation relates the change in vapor pressure with temperature to the heat of vaporization. It provides a way to estimate how the boiling point of a liquid changes when the external pressure is varied, emphasizing the logarithmic relationship between pressure and temperature.

Heat of Vaporization

Heat of vaporization is the amount of energy required to convert one mole of a liquid into its vapor without a temperature change. This thermodynamic property is critical in calculating the temperature-dependent vapor pressure of a substance and plays a key role in applying the Clausius-Clapeyron relationship.

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