00:01
Problem 95 says that benzene is a six -carbon ring with hydrogen attached to each of the carbons.
00:07
This problem instructs you to draw the bluest structure for benzene, including any possible resonance forms.
00:15
So starting off with the information that benzene is a six -carbon ring, what we can do is sort of draw that carbon shell.
00:32
And then as the problem says, each of the carbons in the ring has an attached hydrogen.
00:38
So that gives us the overall formula for benzene is c6h6.
00:57
What you can see here, though, is that with this structure alone, the carbons don't fulfill the octet rule.
01:05
As you'll notice, we've already got three valence electrons associated with each of these carbons, however.
01:13
So the best way to fill the octet of each of these carbons is to strategically place double bond.
01:20
Between carbons in this ring.
01:24
For instance, if you add a double bond here, now these two carbons have their octets filled and each have the appropriate four valence electrons...
