00:02
Option a, we have the conjugate base of benzoic acid.
00:11
So the conjugate base of benjoic acid is formed when benzoyic acid loses a proton.
00:18
So let me represent it.
00:20
H -o -c double bond o.
00:31
So the first one is benzoic acid plus water gives me o negative c double bond o.
00:44
Leads to plus h3o negative.
00:54
It is a conjugate base.
01:03
So moving on to the second one, we have analan.
01:07
Let me draw it, hn plus water, hydrogen, nitrogen positive.
01:34
It is conjugate acid of an alum plus oh negative.
01:55
Moving on to the third option b.
02:01
If an acid is dissolved in water, it reacts with water in equilibrium reaction...