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This is the answer to chapter 24, problem number 45 from the smith organic chemistry textbook.
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And this problem talks about beta -vetivone.
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And so, okay, so we're asked what michael acceptor is needed for the conjugate addition.
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And then we're also asked to draw a stepwise mechanism for the aldol reaction that is the second step in this synthesis.
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Okay, and so this is molecule a, i suppose i should label it.
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And so we're asked in part a of this problem, so let me label that as well.
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We're asking part a what michael exceptor is needed to make the starting material for the aldol reaction.
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And so that michael acceptor is going to look like this.
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And so remember a michael acceptor.
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Is going to be an alpha -beta unsaturated carbonyl compound.
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And so that will be like that.
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And when we do the microreaction between this molecule that i just drew and molecule a, we do get this starting material that we need for the aldol step of this synthesis.
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So next we're asked to draw a stepwise mechanism for that aldol step.
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And so that is going to look like this.
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So the first thing that's going to happen is we have some hydroxide ion here.
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And i just drew a couple structures ahead of time just to try to cut down on the time here.
01:54
So that hydroxide ion is going to grab an alpha proton from the starting material.
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And so that is going to get us to this enolate.
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And then the enolate is going to attack the other carbonyl in this molecule and do the aldol.
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Okay.
02:21
And so that second step there is going to be the one that forms our new six -membered ring.
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So bear with me while i draw this.
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That is terrible looking.
02:33
Let's try that again.
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Better.
02:41
Okay.
02:41
So nothing over here on the left side has changed.
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And now on the right, what we have is this newly formed six -membered ring.
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And so our methyl group will be here.
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Let me move this down...