00:01
Solving problem 43 of chapter 15.
00:04
So we need to explain why the ring present on this molecule called baxter is aromatic.
00:17
So let's start drawing the structure.
00:20
We have benzene down here connecting to a five -member ring that is the isoxazole.
00:35
Methyl, we have an oxygen in here, we have a nitrogen, double bond, double bond, and then it is connected to another benzene ring, connected to sulfur, double bond oxygen, double bomb oxygen, and h2.
01:06
So we want to explain why the is oxoxazole ring is aromatic.
01:11
So first of all, let's indicate that the isosazole ring is aromatic.
01:15
Oxasor ring is this one.
01:18
So let's just rewrite only this portion so that we can focus on what we need to analyze.
01:30
Double bond, double bond.
01:32
We have a metamine here.
01:36
And in here, let's just do that, saying that we have another portion of the molecule.
01:42
And also in here, we have another portion of the molecule.
01:45
Okay, so in order to, for a molecule containing double bones to be called aromatic, he has to satisfy the 4n plus 2 pi electrons, where n can be any number, any integer number like 0, 1, 2, 3, etc...