00:02
Okay, so we've got a couple ways we can do this.
00:04
We can find the successes of the first of exactly one or in exactly two and we can subtract that by one or we can use some previous information that we found and we can do exactly three plus exactly four plus exactly five.
00:22
And i'm going to go ahead and go that route just because i have some of the numbers already with me.
00:27
So if we're doing that, we'll have five choose, five choose three.
00:37
Times 0 .7 cubed, times 0 .3 squared.
00:44
We'll have 5 choose 4, 0 .7 to the 4th, 0 .3, 1, and we'll have 5 factorial, or sorry, 5 choose 5, technically.
01:04
0 .7 to the 5th, 0 .3 to the 0th power.
01:13
And so this is going to end up just being 10.
01:17
So we'll have 10, and i'm going to go ahead and put my ad here...