00:02
Hello, for this problem, we have a tennis ball.
00:07
Given a mass of 57 grams, we're also provided with the time of contact between the tennis ball and the rocket ball, which is 30 milliseconds.
00:22
Over here, you can see that i already converted units, 0 .03 seconds and 0 .057 kilograms.
00:29
Now, the question of this problem is asking you to find the impulse on the first contact when the initial velocity of the serve is 73 meters per second.
00:47
Before starting, we also need to consider that before hitting the ball, it has an initial velocity of zero meters per second in the horizontal direction.
00:59
Also, we need to use the formula of impulse provided on your left, which is equal to the change of momentum, and also is associated to the force times the time.
01:17
All right, let's begin.
01:19
To find the impulse, we can find it as the change of momentum.
01:26
Given that we have two velocities, we can find momentum zero and momentum.
01:34
1.
01:36
Therefore, the change of momentum will be equal to p1 minus p0.
01:45
Remember your formula of momentum, it's equal to mass times velocity.
01:50
In this case, the first momentum is zero, given that the initial velocity was zero.
01:59
For the second one, we're going to multiply the mass times the serving velocity which is 73 meters per second we multiply and we get 4 .161 kilograms meters over second so now change of momentum is equal to the second one 4 .161 minus 0 therefore this one gives me a value of 4 .161 and that's how we find the as the change of momentum.
02:44
Therefore, impulse is equal to 4 .161 kilograms meters over second.
02:54
This is the impulse.
02:57
Second, we are asked to find the force exerted by the tennis player, which in this case, his name is bill.
03:08
Remember that impulse is associated to force with the following formula.
03:15
So given the time of contact, we can find the force...