00:01
In this problem, we have a molecule that is experiencing a drag force, as well as a force -duty electric field.
00:07
So here, i have the equations written out.
00:09
So this fd is our drag -force.
00:12
So drag -force is equal to a constant, which is this k, times the radius of our molecule, times the velocity of the molecule.
00:24
And now the force -dun electric field is simply the charge of the molecule times the electric field.
00:33
Part a asks us to show this relation, that q over r is equal to kv over e, when the two forces balance out of each other, or when they're equal.
00:44
So to do this, we just use these equations up top.
00:48
So when fd is equal to fe, we have that krv is equal to, sorry, is equal to q times our electric field.
01:00
And so all we have to do is rearrange so that on one side we have q over r.
01:07
So let's just divide by r, right? so kv is equal to q over r times the electric field.
01:19
So now we have q over r.
01:20
Now we just need divide by e to get that on the other side.
01:25
So we have kv over e is equal to q over.
01:32
And this is what we need to show.
01:39
So just by rearranging this equation of these two forces equal to each other, we get our answer.
01:48
Part b asks us to find how far does this move after t amount of time.
01:57
Now, since these two forces are balanced with each other, it's going to be moving at a constant velocity...