bio-predictcalculate-blood-flows-through-a-major-artery-at-10-mathrmm-mathrms-for-050-mathrms-then-a

Question

Bio Predict/Calculate Blood flows through a major artery at
1.0 $\mathrm{m} / \mathrm{s}$ for $0.50 \mathrm{s},$ then at 0.60 $\mathrm{m} / \mathrm{s}$ for another 0.50 s through
a smaller artery. (a) Is the average speed of the blood $0.80 \mathrm{m} / \mathrm{s},$
greater than $0.80 \mathrm{m} / \mathrm{s},$ or less than 0.80 $\mathrm{m} / \mathrm{s} ?$ Explain. (b) Verify
your answer to part (a) by calculating the average speed.

Nathan Silvano · Accepted Answer

so problem 18 basic probably team was to know the average velocity of the blood flow and this system. Okay, we know that this system was composed by two parts. The first part. We have a velocity off one meters per second and we spend time that blood spend the time of 0.5 seconds. Okay, The second factory. Or if blood flows with the velocity of 0.6 meters per second. And you also spend the time of 0.5 seconds. Nice. Let&#x27;s see, we know how to calculate every velocity, average velocities, just toto space cover divided by the Toto time that we spent took over the space. Okay, the time we have it&#x27;s just one second. But we don&#x27;t have this space. So we need to find a space so we can calculate the average velocity of the blood flow. Well, let&#x27;s see. We can calculate this place off each party with each artery that the blood flows the first artery. Well, we have one meters per second. That&#x27;s equal X one. There is the first space divided by 0.5. So here we have the first space equals two 0.5 meters Nice and the second after we have a velocity of 0.6. That&#x27;s equal this X to the second space divided by zero point X. This is going to be extra. Ooh equals to 0.6 times 0.5. This is equals to 0.3 meters. Well, why we do this? Because we know how to calculate the average velocity for each part off each after it. So we coakley the space using the equation for average velocity from part one. And for part two, let&#x27;s see now that we have the total space total space that&#x27;s called in Delta X total space Delta X is going to be you 2.5 plus zero point tree. This is RICO&#x27;s too zero point eight meters. Then we come back in here and calculate the average velocity off the blood flow. Lost much of the blood flow. It&#x27;s going to be zero point eight divided by one. This is equal 0.8 meters per second. So what&#x27;s the answers for the first item? The first item he wants to know if the velocity is equal lasts greater than 0.8. Well, the velocities equal in this second night in what is the value of the average velocity? 0.8 meters per seconds? That&#x27;s the final answers. Thank you for watching.

Nathan Silvano · Answer

we&#x27;re our problem 19 similar to probably team because we have a blood full blood flow for two arteries. The force first blood flow has a velocity of one meters per second and covers a distance of 0.5 meters. Second artery. The blood flow as a velocity of 0.6 meters per second and also covers a distance of 0.5 meters. This problem also wants to know what is the average velocity with the blood flow? Well, we know alter, calculate, average velocities, average velocity. It&#x27;s just it Auto space divided by the Toto time. We have the total space. Yes, it&#x27;s just one meter. Total time we have No, this is the problem. So we need to find out what is the total time so we can discover the average velocity Well, just using the average velocity equation for each part or the blood flow we can calculate each time separately. So the first art we have available to you if one meters per second, it is equal to 0.5 divided by thio one. So do you want is just 0.5 seconds. The second part is 0.6 the velocity question 05 divided by teeth too. So the second time hopes the second time is just 0.8 a ate tree tree seconds. So what is the total time called Out? T is just 0.5 less, you know 0.83 tree that&#x27;s equal to 1.333 seconds. Okay, now that we have the total time, it can come back here and discover the average velocity of the blood flow average velocity of the blood flow. It&#x27;s just going to be one divided by one tree tree that&#x27;s equal to 0.7 five meters per second. So the answer for the first item, he wants to know if the velocity of the blood flow average velocity, it&#x27;s going to be equal less or greater than 0.8. So we know that the average velocity this time is less then zero point eight meters per second and the answer for the second night in these what is due actual value off the velocity zero point 75 meters per second. So this is the true masters. Thank you for watching

Donya Dobbin · Answer

All right. So we got some sodium ions flowing in the blood being subjected to a magnetic field which is causing a hall voltage. We need to calculate the velocity of the sodium ions. We can use the hall voltage equation to figure out the velocity, the drift velocity there. So you take the whole of a lot of voltage 0.6 times 10 to the negative three, because is Mila volts. Divide by the magnetic field 0.35 Tesla&#x27;s and divide by the distance, which is 0.5 centimeters. So 0.5 meters. This will give us the velocity, which is 0.34 meters per second. The flow rate, that is how much is going through and a blood vessel is usually a cylinder circular like so we would take the area of the circle, which is pi radius. Let&#x27;s see the diameters 0.5. The radius is 0.25 0.0 25 and meters squared. Pi r squared is the area of a circle multiplied by the velocity, and we will receive the flow rate, which is 6.7 times 10 to the negative six meters cubed per second, and then I would like to figure out which has the higher potential. Um, we have got the magnetic field going to the west, which would be our fingers. Right hand rule fingers. We have got the current, which is going north, which could be Let&#x27;s your thumb. Um all right, I can see you guys all pulling out right hand. Let&#x27;s see fingers thumb up. Promise up. All right, Palm hoops palm is up, and therefore, that is the higher potential, the top, the top of the blood vessel.

Averell Hause · Answer

So here we&#x27;re going to use the equation of continuity. And remember these air only four compressible fluids. And we can say that the cross sectional area, well, a one equals B one. A one times one equals a two times E to sew the volumetric. Basically, the volumetric create eyes going to be equal to the volume of to create throughout the entire ah body. Whether you&#x27;re traveling from the way, order to the arteries or the artist to the aorta, we also have. We can also relate this so we can have the cross sectional area of the aorta times the volume of the aorta equals the cross sectional area of the arteries. Times the sorry, the velocity of the arteries. This will be the velocity of the eye or did not the volume of the area. I apologize, and then we can say that theory radius of oh, aorta will be equal to one point two centimeters. We know that the cross sectional area of the arteries is going to be equal to two point zero centimeters squared, and then we have the velocity at the aorta of forty centimeters per second. And at this point, we can solve. So the of the arteries is going to be equal to the cross sectional area of the aorta. Times the velocity through the aorta divided by the cross sectional area of the arteries. And this is an equal ah, so, um, pie. And then we can say one point two squared. So be pi r squared for the cross sectional area of the aorta. Times forty. The speed the velocity of through the aorta, divided by the cross sectional area of the arteries, which is two point zero, and we&#x27;re approaching ninety point five centimeters per second. So this would be the speed of the blood through the arteries after it has passed through the aorta. And that&#x27;s the end of the solution. Thank you for watching.

Johnny Greavu · Answer

we were asked to interpret the graph a figure p two point nine two on paid sixty five. Let&#x27;s just go through all possible answers. So aids just that the blood flow changes direction. That about point two five seconds. We know that this isn&#x27;t true because the velocity is still positive at twenty five seconds. Yes, it starts leveling out and decreasing, but it is not yet negative and therefore is not change direction. That can&#x27;t be a not trying be pizzas. The speed of the blood phone begins to decrease at about a tenth of a second. We against you that this isn&#x27;t true because the velocity is actually getting steeper. Or, in other words, the rate of change of velocity. With time is increasing, it&#x27;s accelerating speed doesn&#x27;t decrees. It actually increases books. See, this is the acceleration of the blood flow is greatest and magnitude at about a quarter of a second. We see this isn&#x27;t true because at about a quarter of the second, the velocity seems to well, the velocity actually levels out, meaning that the change in velocity is about zero. Meaning the acceleration approximately zero There, Campisi Si, si. That&#x27;s what I&#x27;m that&#x27;s leaves be the acceleration. The board is great. It&#x27;s amazing through that about a tenth of a second I was saying, You see that this is here Because this is where philosophy this is deepest or is curving up the most. The rate of change in velocity with time is increasing. He is a correct.

Eric Mockensturm · Answer

We&#x27;re told that during each heart bank heartbeat, the mass of about 0.8 kilograms of blood is transported. I mean occurs over a time of 0.16 seconds and the blood, the blood transfer transitions from going 0.8 meters per second, up 0.8 meters per second down. So the change in velocity is 1.6 meters per second down and then they ask us what what is the average average acceleration? Well, that&#x27;s simply just the average velocity divided by the time the time change in time. But it started the change in velocity divided by the change in time, and we can just see that pretty much immediately. That&#x27;s 10 meters per second squared and again that is down.

Problem

B1O Predict/Calculate Blood flows through a major…

Problem 18 Easy Difficulty

Answer

(a) Equal
(b) 0.8$\frac{\mathrm{m}}{\mathrm{s}}$

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(a) Equal(b) 0.8$\frac{\mathrm{m}}{\mathrm{s}}$

Physics

Christina K.

Farnaz M.

Zachary M.

Meghan M.

Math Review - Intro

Algebra - Example 1

James S. WalkerPhysics

Andy C.

Marshall S.

Jared E.

Meghan M.

(a) Equal
(b) 0.8$\frac{\mathrm{m}}{\mathrm{s}}$

James S. Walker

Physics