00:01
Considering a dart that's held in somebody's hand, and the dart has a mass m of 0 .01 kilograms, and it's a distance away from the lever point, r of 0 .38 meters.
00:13
The angular acceleration alpha is 35 radiance per second squared, and we're asked to determine the force here if we consider that the rotational inertia of the forearm, i sub a, for inertia of the arm, it's 0 .12 kilogram times meter squared, and the tricep muscle attaches a distance from the elbow joint of 0 .03 meters from the elbow joint, which we call d.
00:37
So the torque that's being placed is equal to the force times the distance from the force, d, which is the 0 .03 meters.
00:46
F here is what we're trying to find, and this is also equal to the moment of inertia times the angular acceleration alpha, where the total moment of inertia is the moment of inertia from the arm, i sub a, plus the moment of inertia.
00:57
From moving the dart at a distance r away from the elbow joint, which is mr squared...