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Black holes with masses smaller than those formed in supernovas may have been created in the Big Bang. Calculate the radius of one that has a mass equal to the Earth's.
$2.36 \times 10^{4} \mathrm{m}$
Physics 103
Chapter 34
Frontiers of Physics
Wave Optics
Particle Physics
Hope College
University of Winnipeg
McMaster University
Lectures
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Interference is a phenomen…
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this problem. We need to find the social radius off a black hole whose mass is eight times the mass of our sun. So you're usedto equation for the radius. So this is the social radius. It is given to be two times g times the mass over C square. Jesus. Any Vince constant and C is the speed of light, so plugging in the values we get when you tense. Constant is 6.67 times 10 to the minus 11 Newton meters square over kilograms square than the mass of the black hole. It is eight times the mass of our sun. The mass of our sun is 1.99 times 10 to the 30 kilograms, a huge number, and we divide this by the speed of light which is three times. Tend to the eight meters per second square meters per second and we square this Upon solving this we get 2.36 times 10 through the four meters, which is nothing but 23.6 kilometers. So the radius of the black hole, whose masses eight times the mass of our sun, is 23.6 kilometers
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