Block A, with a mass of 220 g, is traveling north on a frictionless surface with a speed of 5.0

Name: Problem 62, Chapter 7: Physics
Uploaded: 2020-06-22T20:01:25-08:00
Duration: 1 min 8 s
Channel: Joseph Petrullo
Description: Block A, with a mass of 220 g, is traveling north on a frictionless surface with a speed of 5.0 m / s . Block B with a mass of 300 g travels west on the same surface until it collides with A. After the collision, the blocks move off together with a velocity of 3.13 m / s at an angle of 42.5^∘ to the north of west. What was B 's speed just before the collision?

step 1 So for this question, all we need is the X equation. So initially we have some mass B with some

Question

Block $A,$ with a mass of $220 \mathrm{g},$ is traveling north on a frictionless surface with a speed of $5.0 \mathrm{m} / \mathrm{s} .$ Block $\mathrm{B}$ with a mass of $300 \mathrm{g}$ travels west on the same surface until it collides with A. After the collision, the blocks move off together with a velocity of $3.13 \mathrm{m} / \mathrm{s}$ at an angle of $42.5^{\circ}$ to the north of west. What was $\mathrm{B}$ 's speed just before the collision?

   Block $A,$ with a mass of $220 \mathrm{g},$ is traveling north on a frictionless surface with a speed of $5.0 \mathrm{m} / \mathrm{s} .$ Block $\mathrm{B}$ with a mass of $300 \mathrm{g}$ travels west on the same surface until it collides with A. After the collision, the blocks move off together with a velocity of $3.13 \mathrm{m} / \mathrm{s}$ at an angle of $42.5^{\circ}$ to the north of west. What was $\mathrm{B}$ 's speed just before the collision?

Physics

Alan Giambattista,… 2nd Edition

Chapter 7, Problem 62

Instant Answer

Solved by Expert Joseph Petrullo

06/22/2020

Step 1

Before the collision, the momentum is given by the mass of block B times its velocity, $m_Bv_{B,i}$. After the collision, the momentum is given by the total mass of the system (block A and block B) times the x-component of the final velocity, which is $v_f Show more…

Show all steps

Thanks for your feedback!

Block $A,$ with a mass of $220 \mathrm{g},$ is traveling north on a frictionless surface with a speed of $5.0 \mathrm{m} / \mathrm{s} .$ Block $\mathrm{B}$ with a mass of $300 \mathrm{g}$ travels west on the same surface until it collides with A. After the collision, the blocks move off together with a velocity of $3.13 \mathrm{m} / \mathrm{s}$ at an angle of $42.5^{\circ}$ to the north of west. What was $\mathrm{B}$ 's speed just before the collision?

Play audio

Feedback

Joseph Petrullo and 59 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Conservation of Momentum

This principle states that in an isolated system, the total momentum remains constant before and after a collision. It is applied to relate the momentum components of objects before the collision to the combined momentum after the collision, regardless of the collision type.

Vector Decomposition in Two Dimensions

When dealing with motion in two dimensions, vectors such as velocity and momentum are broken down into perpendicular components, typically along the horizontal and vertical axes. This allows for the separate application of conservation principles in each direction.

Inelastic Collisions

In inelastic collisions, the colliding objects stick together post-collision, meaning that while overall momentum is conserved, kinetic energy is not. This concept is crucial for analyzing collisions where the objects move as a single combined mass after impact.

Please give Ace some feedback