00:01
The probability density function is f of t and the given interval is 1 to 20.
00:04
Now main value is given by mu is equal to integration of 3 into f of t d t.
00:13
Now mu is equal to integration of 1 to 20 which is given.
00:21
Now with the value of f of t which is t l and 20.
00:28
Here t and t will begin sell out so we have only integration of 1 to 20.
00:36
1 by 1120.
00:44
Here 1 by ln20 is constant so integration of constant on is only t as 2 and you to 1.
01:04
Now apply upper limit minus lower limit so our mu is 6 .340 to seconds.
01:32
Now variance is given by integration of x squared into f of x d x minus mu squared.
01:41
So here v is integration of 1 to 20 t square into 1 by t lm 20 minus mu is 6 .342 square.
01:58
Here t squared divided by t is only t.
02:02
And 1 by l20 is constant so take it outside.
02:18
Integration of t is t squared divided by 2.
02:30
Now apply upper limit minus lower limit...