00:01
Here we have a problem of incompressible flow.
00:03
We have our blood artery, which then constricts down somewhat.
00:08
If we have a diameter d at the beginning, and this is going to be our first condition, at our second condition, we have a diameter of 0 .8 d.
00:20
Our velocity inlet is 0 .15 meters per second.
00:28
And this is blood, which is mostly water.
00:30
So we're going to assume a density of 1 ,000 kilograms per meter cubed throughout.
00:39
So the first thing we can start with is bernoulli's equation, which relates the velocity and pressure.
00:49
So p1 plus the static pressure plus the dynamic pressure is equivalent through the streamlines.
01:01
And because we have a closed circuit here, it's through any part of this duct.
01:14
So our pressure difference is going to be p2 minus p1, the traditional way to define pressure difference.
01:25
We can factor out the 1 half rho, because it's constant.
01:28
And then we are left with v1 squared minus v2 squared.
01:35
So we have everything here but v2.
01:38
And to do that, we can use the law of conservation of mass.
01:43
So because there is no blood piling up in this artery, the mass flow, m dot inlet, has to equal to the m dot outlet.
01:55
And we can solve for that.
01:57
So m dot 1 is equal to the second.
02:02
And if we take the density and multiply by the volume flow rate, or we can express the volume flow rate as the velocity times the area, we get our equation here.
02:17
And then because we know the artery is a circle, based on a given diameter, we can start simplifying.
02:26
So our densities cancel out.
02:30
The area of a circle is pi r squared, which is d squared over 2 squared, if we distribute the squared.
02:45
And then v2, so pi, so 0 .8 d squared.
02:51
We can distribute it to 0 .64 d squared over 2 squared.
03:00
Now, most of this cancels...