00:01
Okay, so for this problem, we're given a function that models a person's blood pressure over time, where t is the time of minutes and p of t is the pressure and milliliters of mercury.
00:10
For part a, we're as to find the period of this function p right here.
00:15
Now, if you were looking on the trick function's graph, you can see that the function is cyclical.
00:21
And a period by definition would just be the length of one cycle.
00:24
So it would be the length of this line right here.
00:29
Since this is how often the graph repeats itself.
00:33
Keep in mind, this is the graph of the cosine function, but for a sine function, it would just be the same thing where you look at the y -axis, you see where the graph begins, and you see how often until it repeats itself.
00:45
So for a sign function, the period would be the length of this line.
00:50
However, for this problem, we're not given a graph, we're just given this function right here.
00:55
So for that, you would first make sure that the function is written in state.
01:00
Standard form, which it is.
01:02
For the period, we're going to be looking at this b value right here, which we can see is 160 pi.
01:11
To get the period of any sign or cosine function, the formula that you need to know is 2 pi over b.
01:20
Plugging b in, that is 2 pi over 160 pi, which simplifies to 1 over 80.
01:32
And that is our period right here.
01:35
Again, this is the formula that you need to know, and just know that if the value of b is negative, you would take the absolute value.
01:43
Now, for part b, we're asked to find the number of heartbeats per minute.
01:48
This problem is basically asking us for the frequency, since the frequency is how often something occurs per unit of time.
01:57
For this, you need to know that frequency is the inverse of period.
02:02
Since the period in part a is 1 over 80, the frequency would be 80 beats per minute.
02:09
And that would be your answer for part b.
02:15
Now for part c, we are asked to graph the function.
02:19
For that, we're going to be looking at the standard form of a trick function again, and we're going to assign values to a, b, c, and d.
02:27
A right here is the amplitude, and we can see.
02:31
That that is 25...