Question
Blue manometer fluid of density $925 \mathrm{~kg} / \mathrm{m}^{3}$ shows a column height difference of $3-\mathrm{cm}$ vacuum with one end attached to a pipe and the other open to $P_{0}=101 \mathrm{kPa}$. What is the absolute pressure in the pipe?
Step 1
First, we need to find the pressure difference between the two ends of the manometer. We can use the formula: ΔP = ρ * g * h where ΔP is the pressure difference, ρ is the density of the fluid, g is the acceleration due to gravity (approximately 9.81 m/s²), and h Show more…
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Blue manometer fluid of density $925 \mathrm{kg} / \mathrm{m}^{3}$ shows a column height difference of $3 \mathrm{cm}$ vacuum with one end attached to a pipe and the other open to $P_{0}=$ 101 kPa. What is the absolute pressure in the pipe?
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