Bond angle in $\mathrm{PH}_{4}{ }^{*}$ is higher than that in $\mathrm{PH}_{2}$. Why?

Answer

Related Courses

Chemistry 101

NCERT Class 12 Part 1 - Chemistry

Chapter 7

The p-Block Elements

Section 7

Phosphine

Discussion

You must be signed in to discuss.

Top Chemistry 101 Educators

Allea C.

University of Maryland - University College

Watch More Solved Questions in Chapter 7

Problem 7

Problem 8

Video Transcript

to answer the question why the bond angle of ano, too, is greater or is less than the bond angle of N 02 plus or why. I know two plus has a larger bonding, but we need to draw the Lewis structures. So let's do it for Eno. Nitrogen has five Valence electrons. Each car, each oxygen has six, so that's a total of 17 Valence electrons. We plug in all the 17 valence electrons. Nitrogen has one double bond, one single bond and a single electron on it. So it is somewhere between 120 100 80 degree bond angle. That single electron right here is kind of pushing it out from, um the 100 are actually pushing the this bond angle closer to each other because of its repulsion. That this this electron is repelling these electrons, pushing this bond angle to be something less than 1 80 where, in the case of an 02 plus, there is no single electron pushing this bond angle to be something less than 1 80 so it just stays at 1 80

We have video lessons for 50.00% of the questions in this textbook