Borazine, $\mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}$ (a cyclic compound with alternating $\mathrm{B}$ and $\mathrm{N}$ atoms in the ring), is isoelectronic with benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right) .$ Are there delocalized $\pi$ electrons in borazine? (FIGURE CAN'T COPY)