Question
Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu. Calculate the relative abundances of the two isotopes.
Step 1
811 amu. This is the weighted average of the masses of the isotopes, each multiplied by its relative abundance. We can represent the relative abundance of Boron-11 as x, and the relative abundance of Boron-10 as 1-x (since the total abundance must add up to 1). Show more…
Show all steps
Your feedback will help us improve your experience
Eugene Schneider and 93 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Boron has two naturally occurring isotopes: B-10 with an isotopic mass of 10.013 amu. B-11 with an isotopic mass of 11.009 amu. Calculate the percent abundance for each isotope if the average atomic mass of boron is 10.81 amu.
Boron (B) has two naturally occurring isotopes: boron-10 (abundance $=19.8 \%$ mass $=10.013$ amu) and boron-11 (abundance $=80.2 \%,$ mass $=11.009$ amu). Calculate the atomic mass of boron.
Boron (B) has two naturally occurring isotopes: boron-10 (abundance $=19.8 \%$ , mass $=10.013$ amu) and boron-11 (abundance $=80.2 \%,$ mass $=11.009$ amu). Calculate the atomic mass of boron.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD