00:01
Now we have a vehicle weighing 4 ,500 pounds and an angle of incline of 10 degrees.
00:07
We're trying to find the force required to keep it from rolling down the hill and the magnitude of the force perpendicular to the hill.
00:15
So the force of gravity vector is 0 -4 ,500, and w is going to be cosine 10, sign of 10.
00:24
So v is going to be the dot product of these two vectors.
00:30
So that'll be 0 plus negative 4 ,500, sine 10, all over the magnitude of w, cosine squared 10 plus sine squared 10, all of that squared, times vector w.
00:58
So that ends up being negative 4 ,500 sign of 10.
01:06
10, cosine squared plus sine squared of anything is 1.
01:11
So that's square root of 1 is 1, and it's squared, so that's still 1, times w.
01:19
So vector v, negative 4 ,500, sign 10 is negative 781.
01:29
0 .42 times vector w...